Let n = .99 so 10n = 9.99 Subtracting the first equation from the second yields: 9n = 9 since the repeating decimals subtract out _ which gives us n = 1, but we know that n = .99 so _ .99 = 1
How is 10 X .99 = 9.99? 10 x .99 = 9.9 not 9.99 So n will equal .891 Heres the correct answer: First take the square root of i. Then multiply it by n. So ni. Then multiply ni by .99 If A = b and b*c*a is same as b*a*c, then you have ti multiply 1 by .99ni So you get .99ni Now set that equation equal to 0. And for n you get 0. Then apply ut as a function to find 1 as y. So .99ni = 1 First you multiply .99 by i and you have -.99n =I Then you divide both sides by -.99 you get n=i/.99 now apply that to equation .99i/99=I Take derivative of both sides you get: -2= i/.99 Multiply by .99 squard and find when x limit to 0 and find the y when n is equal to the derivaticlve of the slope. You get x = 1 qnd y = 1. So when .99n = y, .99 = 1 at x = 1