I miss the old days when I had addition and subtraction problems but then again those were boring lol
This thread is sooooooo far ahead of what I'm doing in math Its making me look forward to what's to come
Wow... I'm still stuck doing these [IMG=http://image.tutorvista.com/cms/images/38/rational-expressions.jpg] It's tooo easy (I hope that worked)
The photobucket app works well for uploading photos to these forums. It is a 3rd party app that is allowed to be mentioned for some reason.
My high school didn't have one but my university does. To be honest, if we had a math club at my high school I probably wouldn't have joined but I will gladly join my university's math club next semester
lol I just had a physics final and a lot of it was directly out of my calculus class! Not even stuff from physics class
omg I'm so confused by this! I need to find x 4cos3x 2 = 0 The range is -pi > x < pi Oh and the > and < are larger and equal , and smaller and equal to ) Hope this was clear
Is that 4cos3x plus 2 =0? The plus sign doesn't work on forums. If so, by rearranging you can get cos3x=(-1/2) then you need to ask yourself where is cosine equal to -1/2. Well it's -1/2 at x= (-2pi/3)and (-4pi/3) Now, since the problem is cos3x instead of cost, divide both of your answers by 3. This is because for cos3x, x is being multiplied by 3 so if you divide by 3 then you have what you had initially. Therefore your answer are now x= (-2pi/9) and (-4pi/9) This is assuming that I read your problem correctly and you intended to have a plus sign And btw you wrote your range wrong If you have -pi>x<pi then that reads that x is less than -pi and less than pi. Usually when you have a compound inequality it reads "x is greater than something but less than something else."
If you meant -pi<x<pi then both of these x coordinates satisfy the domain. The "range" usually refers to y. Or you could call it an interval.
typo in second paragraph of my first response to you. Should read: Now, since the problem is cos3x instead of cosx Not cost