Ok so a while ago (a little over a year) I graduated from high school... But I missed the semester for college. And when I finally got to apply, we got the idea to move to a diff state and stuff. But didnt. And missed that semester also. So I missed about a year. And I forgot EVERYTHING related to math! Right now I'm going to classes that help as a guide for the exam. But the teacher explains Nothing! And now May 26th I'm taking the exam that will decide if I make it into the best University (free, cuz its a gov't univ.) and I have to take a 4hr exam. Only 1.3 minutes per question. So I have to do it fast! And my score on the exam along with my HS average depends on it! (obviously) Was wondering if any of you math geniuses could tutor me?? Just little things.. Teach me how to do it.. Not just give the answer. Like this: How in the World do I do that? Help! Serious answers, please. This is serious.
For the last one: Give them all common denominators of six. Combine the left side. x = -1 I'm working my way up. I hate the first one though. >.> I'll pm you a website, too.
11x-y=49 x-y=1 y= x-1 y= 11x-49 I like to get y to one side and x and all other numbers to the other side set them equal to each other since y=y 11x-49= x-1 subtract x from both sides and add 49 to both sides 10x=48 x= 4.8
Or make it into a system of equations. Multiply the second equation by -1. Add the second equation to the first. That would be: 11x - y = 49 - x plus y = -1 You'd then get 10x = 48 Divide by ten, x = 4.8. Then solve for y.
Like I said.... I forgot all this shit years ago. And the exam is simple. It's not like they give us calculus. Just simple things. But most of the people who are in this class are still in HS Im the oldest guy in there but just 1-2 years older. Lol
To check your answer plug x and y back into both equations and make sure it works for both. 4.8(x)-3.8(y)=1 that works. 52.8 (11x)- 3.8 (y)= 49 that works too. So the solution is (4.8,3.8)
This isnt college math... The exam is reviewing all school life, up till like 10th grade. Thats what the exam is about. But i havent done this shit in years
(1/2)x (plus) 7/4 = 9 for this you need a common multiple number in denominator, in other words you need to find a common multiple in the bottom so, it looks like the common multiple is 4 so... (1/2)x you can change to (2/4)x (2/4)x is the same as (1/2)x ... just not simplified now you have (2/4)x (plus) (7/4)x = 9 add it (9/4)x = 9 you add the numberator (top number) in this step, not the denominator (bottom number) next step is multiply both sides by 4 9x = 36 next both sides divide by 9 x= 4
WTF ARE YOU GUYS TALKING ABOUT Dan's was simple. I like it. lol. I remember I used to rock Algebra The only ones I didnt get were these. There are 29 problems tho. #1-24 i aced